54b^2+90b-36=0

Solution for 54b^2+90b-36=0 equation:

54b^2+90b-36=0

a = 54; b = 90; c = -36;
Δ = b2-4ac
Δ = 902-4·54·(-36)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-126}{2*54}=\frac{-216}{108}
=-2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+126}{2*54}=\frac{36}{108}
=1/3
$